In my textbook, the wave-equation for EM waves was derived by using Maxwells' equations in integral form on a EM propgagation in $x$-direction (in vacuum), with E-field in $y$-direction and B-field in $z$-direction.
First, to see if this wave was consistent with Maxwells' equations, one imagined a gaussian closed surface in the shape of a cube, facing in the $x$-direction. $\oint E\cdot ds = Q_{encl}=0$, but $\oint E\cdot ds = A_{y}\times E - A_{-y}\times E$. Therefore must E be equal on both sides, and furthermore homogenous in each $yz$-plane.
But one can in principle make this gaussian surface as streched in the y-direction as one want, and not necessarily centered on the axis of propagation. If you create a surface with $A_{-y}$ just below the $x$-axis and, let's say, $A_y$ three lightyears over the $x$-axis. Then, by the same logic, the E-field has to be of equal magnitude over there...
So does, as the wave-propagates, the electric and magnetic field instantly appear in an infinitely large plane perpendicular to the direction of propagation, or am I misinterpreting something here? I probably am...
The solution being considered here, a plane wave, is indeed constant at any time on a plane orthogonal to the direction of propagation. It's safe to say there are no "real" plane waves in the world. However, they are still important because