Is there a formula for $\mathcal{L}(f(t+1))$? in terms of $\mathcal{L}(f(t))$?
I know for example $$ \mathcal{L}(f(t-a)\cdot u(t-a))=e^{-as}\mathcal{L}(f(t)) $$
Is there a formula for $\mathcal{L}(f(t+1))$? in terms of $\mathcal{L}(f(t))$?
I know for example $$ \mathcal{L}(f(t-a)\cdot u(t-a))=e^{-as}\mathcal{L}(f(t)) $$
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