Let $f:[0,1] \to [0,1] $ be a lower semicontinuous function. I am interested in the set $$ S:= \left\{t\in (0,1] : \liminf_{s\nearrow t} f(s) > f(t)\right\}$$
Is there an example for which this is uncountable?
Note that $S$ is a subset of the points of discontinuity of $f$.
Motivation: I have some involved arguments in some other context (beginning with an arbitrary lower semicontinuous function), which suggest that this set is countable. I mistrusted this outcome and already checked for a weak link in the argumentation, which relies on the lower semicointinuity. But I did not find a weak link. Before I try to find something which probably isn't there I want to try to answer this question. A reference is also welcome.
What I've tried:
I tried to construct a function $f_C$ of the form $$f_C (t) := 1_{[0,1]\setminus C}(t),$$ where $C$ is a closed set (so the (fat) Cantorset is possible). But then $$S= \{ t \in (0,1]\cap C\; \vert\; \exists a < t : (a,t)\cap C = \emptyset \}$$ which is countable, because one can map it injectively into the rational numbers.
Without success I investigated $$S_\varepsilon := \left\{t\in (0,1] : \liminf_{s\nearrow t} f(s) \geq f(t)+ \varepsilon\right\}$$ because I suspected also a isolated-from-left structure.
Here is another proof:
Let $f:[0,1]\to \Bbb R$ be lower semicontinuous. If $$t_0 \in S_f := \left\{ t\in (0,1] : \liminf_{s\nearrow t} f(s) > f(t)\right\}$$ then there are $\varepsilon, \delta >0 $ such that $$ z := f(t_0) +\varepsilon \leq f(s) \quad \forall s \in (t_0-\delta , t_0).$$
Further, since $f$ is lower semicontinuous, we have that there is $x\in \Bbb R$ with $$x < y:=\inf_{s\in [0,t_0-\delta]} f(s).$$
Now, let $(B_t)_{t\geq 0 }$ be a standard Brownian motion and define $W_t := B_t +x$. Furthermore, define $$\tau_f := \inf\{t > 0: W_t \geq f(t)\},$$ which is measurable since $f$ is lower semicontinuous. Now observe that $$\Bbb P( \tau_f = t_0) \geq \Bbb P(\tau_y > t_0 -\delta , \tau_z > t_0 , W_t \in (f(t_0), z))\\ = \Bbb P \left(\sup_{s\in [0,t_0 -\delta]} (B_s +x) < y, \sup_{s\in [t_0 -\delta ,t]}(B_s +x) < z, B_{t_0} + x \in (f(t_0) , z)\right) >0.$$ This implies that $$S_f \subseteq \{t \geq 0 : \Bbb P (\tau_f = t_0) > 0\}.$$ But the set on the r.h.s. is countable.
If $f: [0,1] \to [0,1]$ is an arbitrary function, then $$f_* (t) := \min \left(\liminf_{s\to t}f(s) , f(t)\right)$$ is lower semicontinuous and $S_f \subseteq S_{f_*}$.