Is there a way of approximating a percentage decrease with the natural logarithm?

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my question stems from this nice approximation of a percentage increase: for small percentage increases (usually below 20%), we can have an approximation with the natural log of the ratio. Here's an example:

50 increases to 55 --> % increase is (55-50)/50 (usually multiplied by 100, but let's keep it decimal for the time being)

OR

we could approximate it and say it is ln(55/50) or ln(55)-ln(50).

My question, then, is: is there a way to approximate a percentage decrease as well?

Think of it as a discount: the price was 55 and now it's 50. The discount is 1 - 50/55, or (55-50)/55. However, I really can't find a log approximation that simulates what the other one does and has the two following properties:

  1. The values of the percentage decrease and the approximation are similar for small percentage decreases.
    1. As the decrease gets larger (say, for instance, from 1000 to 50), the function (I'm assuming it'll be a log) keeps smoothing the decrease in a monotonic way (so from a linear enlargement of the decrease, we get a marginally diminishing one, just as it happens for the increase in the initial example).

Any ideas?


One thought I had was that, in general terms, you can positively express an increase as $(b-a)/a$ and a decrease as $(b-a)/b,$ so to get from the second to the first you can multiply the second by a/b. So you can find something decent with $\ln(b/a)*a/b$. If you do that, however, you end up with something like: $$ \begin{array}{lll} ~ & \text{% Decrease} & \text{Log decrease} \\ 50 & 0.0909 & 0.086645618 \\ 60 & 0.1667 & 0.151934631 \\ 100 & 0.5000 & 0.34657359 \\ 500 & 0.9000 & 0.230258509 \\ 1000 & 0.9500 & 0.149786614 \\ \end{array} $$