I know there are integral representations for $\zeta(x) , \Gamma(x) $ and even $\zeta(x) \Gamma(x)$.
I wonder Is there an integral representation for $\arctan(x) \zeta(2x)$ ?
$\arctan(x) \zeta(2x) = \int_0^{\infty} g(x,t) dt$
Probably.
I know there are integral representations for $\zeta(x) , \Gamma(x) $ and even $\zeta(x) \Gamma(x)$.
I wonder Is there an integral representation for $\arctan(x) \zeta(2x)$ ?
$\arctan(x) \zeta(2x) = \int_0^{\infty} g(x,t) dt$
Probably.
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