Is there an irreducible polynomial over $\mathbb{Z}[x]$ with setwise coprime coefficients that is composite for all integer arguments?

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There are lots of questions here and on the web about polynomials that produce prime values. I'm asking the opposite: is there a nontrivial polynomial $p(n)$ that never produces primes?

Specifically, the polynomial must:

  1. be irreducible over the integers
  2. have coefficients that as a set have a greatest common divisor of 1
  3. evaluate to a composite number for all integer arguments.

I suspect that such a polynomial does not exist. I've tried using the set of prime factors of $p(0)$ (the constant term) and $p(1)$ (the sum of coefficients) to generate an argument $m$ such that $p(m)$ is relatively prime to each of $p(0)$ and $p(1)$, but I can't really get anywhere with that approach. I don't have any other ideas of what to try.

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The problem is that a polynomial in $\mathbb{Z}[x]$ can be primitive, yet some $d>1$ divides all of the numbers $P(n)$. No surprise, the polynomial $\frac{P(x)}{d}$ must have all values at natural numbers integral. Such polynomials are characterized as linear combinations of $\frac{x(x-1)\cdots (x-k+1)}{k!}$ with integral coefficients. Now multiplying by some integers, we can ensure that the polynomial is in $\mathbb{Z}[x]$, primitive, yet the numbers $P(n)$ have a common divisor.