Is there something wrong with brackets? $f(2x+(f(y)+f(f(y))=4x+8y$

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$ x,y \in\mathbb{R}$ and $f:\mathbb{R} \rightarrow \mathbb{R}$, find a function that,

$$f(2x+(f(y)+f(f(y))=4x+8y$$

A) $f(x)=2^x$

B) $f(x)=2x$

C) $f(x)=2^x-3$

D) $f(x)=2x^2-3$

E) $f(x)=4x-2$

My problem is,it seems to me that there's something wrong with brackets. Or do I think wrong?

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Looks like the red parenthesis is superfluous: $$f(2x+\color{red}{(}f(y)+f(f(y))=4x+8y$$ since $$f(y)+f(f(y)) = \color{red}{(}f(y)\color{red}{)}+f(f(y)) = \color{red}{(}f(y)+f(f(y))\color{red}{)},$$ so let us just ignore it.

That leaves us with three cases:

  1. $f(2x\color{blue}{)}+f(y)+f(f(y))=4x+8y$
  2. $f(2x+f(y)\color{blue}{)}+f(f(y))=4x+8y$
  3. $f(2x+f(y)+f(f(y))\color{blue}{)}=4x+8y$

I believe the correct one should be 2., since it's the only one that one of the proposed solutions works for.