In 2 dimensions $Y=cX+B$ is a line. In 3D $Z=aY+bX+C$ is a plane...
But this won't be a line: $f(x)=1/(1+e^-5x)$.
And how is this a plane?
2026-04-08 16:17:15.1775665035
Is this equation expected to be a plane? How can I get some better intuition?
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No, it is not a plane. The graph looks like a plane because it was drawn with $(x,y)\in\left[-\frac12,\frac12\right]\times\left[-\frac12,\frac12\right]$. If you choose $[0,1]\times[0,1]$ instead, then you will get this: