$f(x) = \left(1-\frac ax\right)^2$
where both $x>0$, $a>0$
Is this function bounded? i.e. is there an M such that $f(x) ≤ M < \infty$ ?
How can I figure this out?
Thanks very much in advance and apologies for notation, I am newbie.
$f(x) = \left(1-\frac ax\right)^2$
where both $x>0$, $a>0$
Is this function bounded? i.e. is there an M such that $f(x) ≤ M < \infty$ ?
How can I figure this out?
Thanks very much in advance and apologies for notation, I am newbie.
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No. Let $a > 0$. Then, since $f(x) = (1-\frac{a}{x})^{2} \to \infty$ as $x \to 0+$, the function $f$ is unbounded on $]0, \infty[$.