Is this function $$x1_{\{x>0\}}(x)$$ Lipschitz? It's not differential so mean value cant be used here.
2026-03-25 16:20:45.1774455645
Is this function involving indicator function Lipschitz?
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Yes. You only need $|f(x)-f(y)| \le K |x-y|$, and $K=1$ will do.