Is this polynomial irreducible over rationals?

56 Views Asked by At

$f(x)=1+x+\frac{x^2}{2!}+\dots+\frac{x^n}{n!}$.

I know that if n is prime, time $n!$ on both sides, since $n$ is prime, Eisenstein criterion shows $f(x)$ is irreducible. Is it also true for arbitrary finite positive integer $n$?

1

There are 1 best solutions below

0
On BEST ANSWER

Yes...but I have not seen a short proof.

here is a (not short) proof.