Given $A+B=\frac{\pi}{4}$, find $(1+\tan A)(1+\tan B)$
My attempt:
Since $\tan(A+B)=1=\frac{\tan(A)+\tan(B)}{1-\tan(A)\tan (B)}$, therefore $\tan(A)+\tan(B)+\tan(A)\tan(B)=1$, therefore, $1+\tan(A)+\tan(B)+\tan(A)\tan(B)=2$ Is it correct?
2026-05-16 23:55:42.1778975742
Is this solution correct
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