Given language $L$ of type-2 (Chomsky hierarchy) and a language $L'$ of type-1 or type-0 ("more general" I would say) what will be the type of $L'' = L \cup L'$? (also in Chomsky hiearchy)
2026-03-26 09:17:53.1774516673
Is union of context-free and more general language still context-free or more general language?
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Type-1 languages are closed under union so $L_2 \cup L_1$ cannot be type-0.
However, it could be pretty well anything else, even type-3. For example, context-free languages are not closed with respect to complement, so there is at least one context-free language $L_2$ such that $\bar L_2$ is type-1. However, $L_2 \cup \bar L_2$ is $\Sigma^*$, which is regular (type-3).