Does there always exist an isometric embedding from $X$ to $\mathbb{R}^4$ for finite $X$.
I think yes, because I think every finite space can be isometrically embedded to a Hilbert space. Any ideas. Thanks.
Does there always exist an isometric embedding from $X$ to $\mathbb{R}^4$ for finite $X$.
I think yes, because I think every finite space can be isometrically embedded to a Hilbert space. Any ideas. Thanks.
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Hint: Consider a lower dimensional analog. Is this possible for $\Bbb R^2$? What if we have $4$ equidistant points?
Of course, we can embed these points in $\Bbb R^3$ as the vertices of a regular tetrahedron.