Justify $ f(z)g(z) := \sum\limits_{j=0}^{\infty}\varphi_j z^j$ for $|z|\leq 1$

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Let $\psi_j$ be a sequence of comlex numbers such that $\sum\limits_{j=0}^{\infty}|\psi_j| < \infty$. Then $$ f(z) = \sum_{j = 0}^{\infty}\psi_jz^j $$ is a holomorphic function on $|z|<1$ since the series converges absolutely. Now let $g(z)$ be a complex polynomial.

I want to understand/justify the following relation:

$$ f(z)g(z) = \sum_{j=0}^{\infty}\varphi_j z^{j} \qquad \text{for} \quad |z|\leq 1. $$

My ideas:

  1. $f(z)g(z)$ is holomorphic on $|z|<1$ as a product of two holomorphic functions on $|z|<1$. So there exists a Laurent series for the product on the open unit ball $|z|<1$.
  2. To justify the above representation for the closed ball $|z| \leq 1$, I think of considering a holomorphic extension of $f(z)g(z)$ which would also be defined in the neighborhood of the unit circle and coincide with $f(z)g(z)$ on $|z| \leq 1$.
  3. Or maybe I should consider a holomorphic extension of $f(z)$.

But I am unsure whether it is possible or whether there is a better way to understand/interpret/justify the above equation.