Kernel of a map $\phi: \mathbb{C^*}^3 \to \mathbb{C^*}^2$

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I cannot understand which is the kernel of the following map $\phi: \mathbb{C^*}^3 \to \mathbb{C^*}^2$ with $$ (t_1,t_2,t_3) \mapsto \left(\frac{t_2}{t_1}, \frac{t_3}{t_1}\right) $$ In other words I do not see which elements of $ \mathbb{C^*}^3$ map to zero in $ \mathbb{C^*}^2$ under $\phi$. Of course $t_1$ cannot be because we divide by it. Therefore which ones belong to the kernel?

Note that this is the standard map induced when one tries to construct toric projective varieties.

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First of all, the map is clearly not a map from $\mathbb C^3$ to $\mathbb C^2$, but a map from $C^3\setminus\{(0,t_2,t_3)|t_2,t_3\in\mathbb C\}$ to $\mathbb C^2$. The map is clearly undefined on $(0,1,1)$ for example.

Now, if $\phi(t_1,t_2,t_3)$ is defined, then you can find the kernel using this hint: $$\frac{t_2}{t_1} = 0 \iff t_2 = 0$$