Kiselev's Geometry Problem 102

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Prove Theorem: A median in a triangle is equidistant from the two vertices not lying on it.

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Let AD be the median in the triangle.

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It means we have to prove that BX = CY where X and Y are the feet of the perpendiculars from B and C to the median AD respectively.

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This follows immediately after showing the blue triangles are congruent.