$L/k$ and $K/k$ field extensions of $k$ with $[L:k]=m,[K:k]=n, (m,n)=1\implies L\cap K=k$

43 Views Asked by At

$L/k$ and $K/k$ field extensions of $k$ with $[L:k]=m,[K:k]=n, (m,n)=1\implies L\cap K=k$.

The first thing I taught is that if $\alpha\in L,\beta\in K$ are algebric over $k$, the degrees of the minimal polynomials must not divide each other, so the minimal polynomials cannot divide each other... but obvsiouly, there is nothing saying that exists some algebric element, so what can I do?

1

There are 1 best solutions below

2
On BEST ANSWER

Clearly $F=L\cap K$ is a field extension of $k$ such that both $L$ and $K$ are field extensions of $F$. Then $$m=[L:k]=[L:F][F:k]$$ and $$n=[K:k]=[K:F][F:k]$$ implies that $[F:k]$ is a common divisor of $m$ and $n$. What next?