The relationship between two functions f and g is written as $f (x) = o (g (x))$
Show that $tan (x^3 ) = o (x^2 )$
By the epsilon-delta definition, there exist $\epsilon{}>0$ and $\delta{}>0$ such that $|\frac{tan(x^3)}{x^2}|<\epsilon$ whenever $|x-x_0|<\delta{}$. How can you choose $\delta{}$ such that $|\frac{tan(x^3)}{x^2}|<\epsilon$
Exhibiting $\delta$ explicitly in terms of $\varepsilon$ is rather messy. But you can see such $\delta$ exists because the expression is
$$\frac{x}{\cos (x^3)} \frac{\sin(x^3)}{x^3}$$
and we have that