LaPlace Derivative Thereom

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No idea what this is saying...

The real part (or is it the magnitude of the complex f(t)) is less than Me^{yt}. Why is y any real number, and not restricted to say > 0.

Then 1.3, taking the laplace transform of the function derivative. Why is (s) outside? Shouldn't it be written L(f'(s))?

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Fairly stumped at what this is trying to tell me

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Write (1.3) as $L(f')(s) =sL(f)(s)-f(0) $.

Putting $f'$ for $f$, this becomes $L(f'')(s) =sL(f')(s)-f'(0) $.

Putting (1.3) in this, we get $L(f'')(s) =s(sL(f)(s)-f(0))-f'(0) =s^2L(f)(s)-sf(0)-f'(0) $.

By induction, we can get a formula for $L(f^{(n)})(s) $.