We know that Laplace distribution has a form of $f_x=\frac{1}{b}*e^{(-\frac{|(x-\mu)|}{b})}$
Is it true to call the $f_x=\frac{1}{b}*e^{(-\frac{|(g(x)-\mu)|}{b})}$ distribution as generalized Laplace distribution?
We know that Laplace distribution has a form of $f_x=\frac{1}{b}*e^{(-\frac{|(x-\mu)|}{b})}$
Is it true to call the $f_x=\frac{1}{b}*e^{(-\frac{|(g(x)-\mu)|}{b})}$ distribution as generalized Laplace distribution?
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