Laplace Transform for differential equation

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In the text, I'm given with the following system of differential equations:

$$y_1'=-y_1+4y_2$$ $$y_2'=3y_1-2y_2$$

where $y_1(0)=3$ and $y_2(0)=4$

In the answer book, by doing Laplace transform it obtains the following system of differential equations:

$$(s-2)Y_1+3Y_2=1$$ $$-Y_1+(s+2)Y_2=0$$

How did it calculate this?

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It's a typo. The correct LT for the system is as follows: \begin{align*} sY_1-y_1(0)&=-Y_1+4Y_2\\ sY_2-y_2(0)&=3Y_1-2Y_2\\ \\ sY_1-3&=-Y_1+4Y_2\\ sY_2-4&=3Y_1-2Y_2\\ \\ (s+1)Y_1-4Y_2&=3\\ -3Y_1+(s+2)Y_2&=4. \end{align*} Then continue.