Laplace transform of $\sin(\pi|t-1|)$.

Question

Hi guys i have to transform this :

$$\sin(\pi|t-1|)$$

$(0,+\infty)$

I was thinking of multiply it for $u(t-1)$ (leaving the $+$) and then multiplay for $u(t)-u(t-1)$ but changing with the $-$ is this a good way?