Laplace transform to minus infinity

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This is a solution to $f(t) = \Theta(t) - 1$ found in my textbook.

$$ Lf(s) = \int^{+\infty}_{-\infty} e^{-st}(\Theta(t) - 1) dt = \int^0_{-\infty} e^{-st} (-1) dt = \left[ \frac{e^{-st}}{s} \right]^0_{-\infty} = \frac{1}{s} \left(1 - lim_{a \rightarrow -\infty} e^{-as} \right) = \frac{1}{s} $$

The thing that bothers me is that $\lim_{a -> -\infty} e^{-as} = 0$ in the solution but for me (and wolframalpha) it should be $\infty$.

I've encountered a similair problem at on other exercise, which means I think I've wrong somewhere. Please explain why the lim-term is 0.

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The laplace transform is $\frac{1}{s}$, but you forgot the region of convergence for the integral, says $\Re(s) < 0 .$ Actually,

$$\lim \limits_{t \rightarrow -\infty}e^{-st} = 0, \hspace{3mm}\text{for}\hspace{3mm}\Re(s) < 0. $$