I have been trying to preform laplace transformation on $10e^{0.5t-1} u(t+2)$.
So here's how I tried to solve it using general formula for laplace transformation:
$ X(s) = \int_{-\infty}^{\infty} 10e^{0.5t-1}e^{-st} u(t+2)dt $
$ X(s) = \int_{-2}^{\infty} 10e^{t*(0.5-s)-1}dt $
$ X(s) = -\frac{10e^{2s-2}}{0.5-s} $
But this seems to be wrong answer, so I am confused now because when I run the problem on wolframalpha i get the answer:
$ \frac{3.67879}{s-0.5} $
I am realy trying to understand what's going on here, because I get the wrong answer every time I try to solve it and I can't see where is mistake, any help would be appreciated.