How would I go about expanding this expression $$ f(x) = x\arctan(x)$$ into Laurents series at $x=\infty$. Substituting $y=\frac{1}{x}$ does not help me here, or I just do not understand how it would help.
2026-03-26 20:16:58.1774556218
Laurent series at infinity for $f(x) = x\arctan(x)$
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Hint: $\arctan x=\frac{\pi}{2}-\arctan{\frac1x}$ for all $x>0$