Laurent series of $\ln(1-\frac{2i}{z+i})$

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How to find Laurent series of function $ln\left(1-\frac{2i}{z+i}\right)$ if it is known $1 \leq |z| \leq 2$.

I am confused how to find this, because I tried to prove that $|\frac{2i}{z+i}|<1$ and use formula for $\ln$ series around $0$ but didn't succeed.