Law of Sine Problem

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I know the law of Sine. SinA/a=SinB/b=SinC/c

I think I'm missing something here... I am given ∠A=68.41°,∠B=54.23° and a=12.75ft. I found b with no trouble which is 11.119ft. I used SinA/a=SinB/b... But I cannot figure out how find ∠C and c.

Please help

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Hint: The angles of a triangle add to 180 degrees. Can you take it from here?