I have just seen the tensor algebra for a Lie algebra. Let $\mathfrak{g}$ be a Lie algebra, and let $T(\mathfrak{g})$ be its tensor algebra.
I am told this is a Hopf algebra with coproduct $\Delta(x)=x\otimes 1 + 1\otimes x$. This confuses me.
The tensor algebra is $T(\mathfrak{g})=\Bbb C\oplus \mathfrak{g}\oplus (\mathfrak{g}\otimes \mathfrak{g})\oplus \cdots$.
I take it then, that $T(\mathfrak{g})\stackrel{\Delta}{\longrightarrow} T(\mathfrak{g})\otimes T(\mathfrak{g})$.
So that $x\otimes 1$ lives in $T^1(\mathfrak{g})\otimes T^0(\mathfrak{g})$ and $1\otimes x \in T^0(\mathfrak{g})\otimes T^1(\mathfrak{g})$.
But I must be careful:
- There is an isomorphism $(A\oplus B)\otimes C \cong (A\otimes C) \oplus (B\otimes C)$ and the same for left tensors. But this was for $R$-modules where $R$ is a commutative ring. Each of $\mathfrak{g}^{\otimes n}$ can be treated as $\Bbb C$-modules, so I suppose I can use this here?
- Above was finite though. Do I get a similar distributivity for the infinitely many terms in the direct sum case?
- Can I deduce that $T(\mathfrak{g})\otimes T(\mathfrak{g})= \displaystyle\bigoplus_{i+j=d, \,\, d\in \Bbb Z^+_0}( T^i(\mathfrak{g})\otimes T^j(\mathfrak{g}))$ (I mean, is this true, rather than; does it immediately follow from above)
We say $T(\mathfrak{g})$ is a 'Hopf-algebra' because it has mapps out of itself in particular ways. This doesn't mean we say $\Delta(x)$ is in the hopf algebra or anything right? It's simply that it has some nice structure regarding maps out of itself?
I think that you might be heading in the wrong direction to understand this definition, so I'll explain a way to interpret it. I won't use any facts about Lie algebras, so let $V$ be a vector space. I want to define a map $$ \Delta: T(V) \to T(V) \otimes T(V)$$ such that for all $x \in V$, $$ \Delta(x) = x \otimes 1 + 1 \otimes x$$ and somehow "extend this up to all of $T(V)$". Here is what is intended by this:
After this, you need to check that $\Delta$ actually does what it should in the Hopf algebra: it plays well with the counit, is coassociative, etc.
These definitions are quite easy to use. For example, if $x, y \in V$, then we can find that
$$\begin{aligned} \Delta(xy) &= \Delta(x) \Delta(y) & \text{Since $\Delta$ is a map of algebras}\\ &= (x \otimes 1 + 1 \otimes x)(y \otimes 1 + 1 \otimes y) \\ &= xy \otimes 1 + x \otimes y + y \otimes x + 1 \otimes xy & \text{By algebra structure on $A \otimes B$} \end{aligned}$$