I am trying to find a least-squares ellipse fit for a set of 100 data points $(x,y)$.
Now I have found the values of $A,B,C,D,E,F$ according to the conical equation of the ellipse $$ Ax^2+Bxy+Cy^2+Dx+Ey+F=0 $$ I would like to know how to find the points that actually lie on this ellipse. From my basic understanding, if I substitute a value of $x$ in the above equation, it should give me the corresponding value of $y$.
When I do the above, I get a straight line and not really a fitted ellipse. How can I find the fitted ellipse?
My task is to plot these points so that I can see the best possible fit. For reference see [link]. This is the source of ellipse fitting that I am currently using.
I appreciate help from anyone who has experience with this. I am sorry if I am lacking some basic mathematical knowledge, but from what I understand, it isn't all that straightforward.
Regards
Arj
Given a ellipse as
$$ E(x,y)=Ax^2+B xy+Cy^2+D x+ E y + F=0 $$
and a data set as $(x_k,y_k),\{k=1\cdots,n\}$ a typical fitting process is to minimize the residuals at each point, squared so defining
$$ R(A,B,C,D,E,F) = \sum_{k=1}^nE(x_k,y_k)^2 $$
the problem reads as
$$ \min_{A,B,C,D,E,F}R\ \ \ \ \text{s. t.}\ \ \ \ \cases{B^2\lt 4A C\\ A^2+B^2\gt \mu} $$
those restrictions are needed first to guarantee that the fitted conic is an ellipse and second to avoid the undesirable trivial minimum $A=B=C=D=E=F=0$. Follows a MATHEMATICA script showing the procedure