Lebesgue and Riemann integrals two proofs

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1.

Let X be a finite closed interval [a,b] in R, let X be the collection of Borel sets in X and let λ be a Lebesgue measure on X. If f is a nonnegative function on X, show that fdu =∫a->b f(x)dx

I know that the right side denotes the Riemann integral of the function. and I am given the hint that first establish this equality for a nonnegative step function (a linear combo of characteristic function of intervals.)

2.

A slight change, let X=[0, +∞) let X be the Borel subsets of X let λ be a Lebesgue measure on X. If f is a nonnegative function on X, show that fdλ =lim b ->+∞ ∫0->b f(x)dx

It means that the Lebesgue and the improper Riemann integrals coincide. But how to show

fdλ =lim b ->+∞ ∫0->b f(x)dx

Please help prove the two similar questions in details. Thanks!

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(1) If $f : X= [c,d] \to \mathbb{R}$ is a nonnegative Riemann integrable function, then

$$\int_c^d f(x) \, dx = \sup_{\phi \leqslant f} \int_c^d\phi(x) \, dx = \inf_{\psi \geqslant f} \int_c^d\psi(x) \, dx ,$$

where $\phi$ and $\psi$ are step functions. This is straightforward to show using upper and lower Darboux sums and integrals.

Since any step function is a simple function, we have for simple functions $\hat{\phi}$ and $\hat{\psi}$

$$\sup_{\phi \leqslant f} \int_c^d\phi(x) \, dx \leqslant \sup_{\hat{\phi} \leqslant f} \int_{[c,d]}\hat{\phi} \leqslant \inf_{\hat{\psi} \geqslant f} \int_{[c,d]}\hat{\psi} \leqslant \inf_{\psi \geqslant f} \int_c^d\psi(x) \, dx ,$$

and Riemann integrability implies Lebesgue integrability with

$$\int_{[c,d]}f= \int_c^df(x) \, dx .$$

The converse is not true. Lebesgue integrability does not imply Riemann integrability -- even on a finite interval. (Consider the Dirichlet function).

(2) Note that by the monotone convergence theorem, if $f$ is nonnegative and is improperly Riemann integrable, then

$$\int_{[a,\infty)}f = \lim_{n \to \infty} \int_{[a,\infty)} f 1_{[0,n]} = \lim_{n \to \infty} \int_a^n f(x) \, dx = \int_a^{\infty} f(x) \, dx$$

since the Riemann and Lebesgue integrals coincide on bounded intervals.