Lebesgue ball integral and $r^n$ terms

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So I'm trying to understand how to calculate ball integrals in measure theoretic way:

$\int_{\mathbb{R}^n \setminus B(0,r)} \frac{1}{|x|^{\alpha}}dx$

$=\int_{\mathbb{R}^n} \frac{1}{|x|^{\alpha}} \chi_{\mathbb{R}^n \setminus B(0,r)} (x)dx$

$=r^n\int_{\mathbb{R}^n} \frac{1}{|rx|^{\alpha}} \chi_{\mathbb{R}^n \setminus B(0,r)} (rx)dx$ $=...$

as written in this, page 3.

First two lines are clear, but I don't understand what happens in the third line. $r^n$ comes from somewhere, one adds $r$ inside $\chi$ and then there's $r^{\alpha}$ added to the integrand. What, why?


The linked paper also has this short theorem or lemma on top of p. 3, which gives a formula for

$$\int_{\mathbb{R}^n} f(|x|)dx=\omega_{n-1} \int_0^{\infty} f(r)r^{n-1} dr$$

I wonder if this can be found elsewhere?