Lebesgue integral: intuition

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I was reading this beautiful discussion about the difference between Riemann and Lebesgue's integral .

Lebesgue integral basics

What is not clear to me is the following: if we are computing the area we are computing the portion of the graph of $y=f(x)$ that lies between the horizontal lines $y=y_i$ and $y=y_{i+1}$, why do we approximate it by using $ \sum_{i=0}^{n-1} \mu(E_i)y_i^*$? Should not it be $\sum_{i=1}^{n} \mu(E_i)(y_i- y_{i-1})$, where $y_i- y_{i-1}$ would be the "height" and the measure $\mu(E_i)$ , assuming the domain of $f$ is $R$, would be the "length"?

Edit:

For instance, suppose I am approximating the area under the curve in figure 2 below through the red rectangles. Why do not we use simply $\sum_{i=1}^{n} \mu(E_i)(y_i- y_{i-1})$? For instance, the area of the rectangle on top, should be simply $\mu(E_n)(y_n- y_{n-1})$. Where $\mu(E_n)$ is $(x:y_{n-1}<f(x)<y_n)$. What is wrong with my reasoning?

comparision of integrals

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You have to realize that the $E_i$ is exactly the set of $x$-values where $y_i<f(x)\leq y_{i+1}$.

I find it more intuitive to think of $y^*_i$ as the height and $\mu(E_i)$ as the "length". It just happens that it might be the length of something that isn't and interval and therefor doesn't have a "natural" length. The length might need to be computed using more complicated techniques, hence the development of the Lebesgue "length" measure.