Let $\phi(x)$ be a formula. What does $\forall z\forall y((\phi(x)\land\phi(y))\to z=y)$ assert? ("Set Theory: A First Course" by Daniel Cunningham)

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I am reading "Set Theory: A First Course" by Daniel Cunningham.

There is the following exercise in this book (Exercise 1.4.6 on p.23):

Let $\phi(x)$ be a formula. What does $\forall z\forall y((\phi(x)\land\phi(y))\to z=y)$ assert?

My 1st answer is here:

If $z\neq y$, then $\phi(x)$ or $\phi(y)$ doesn't hold.

My 2nd answer is here:

$\phi(x)$ doesn't hold or if $z\neq y$, then $\phi(y)$ doesn't hold.

My 3rd answer is here:

$\phi(x)$ doesn't hold or if $\phi(y)$ holds, then $z=y$.

Are my answers ok?

By the way, there is the following exercise in this book (Exercise 1.4.1 on p.23):

What does the formula $\exists x\forall y(y\notin x)$ say in English?

I guess the correct answer is $x=\emptyset$.
Is the following answer ok or not? :

There exists a set $x$ such that $y\notin x$ for all $y$.