$\lim_{x\to 0}\frac{\arcsin x}{x}=1$

Question

I am trying to show that $$\lim_{x\to 0}\dfrac{\arcsin x}{x}=1$$ I am new to inverse trigonometric functions, so I am sorry if it's obvious.

So if we put $\arcsin x=t,$ then $\sin t=x$. How do I say where t goes when $x\to 0$?