I was just informed that
$$\lim_{x \to n\pi} \dfrac{M^{2}\cos(2Mx)}{\cos(2x)} = M^2,$$
where $n$ is an integer.
What are the steps for calculating this?
I would greatly appreciate it if people would please clarify this.
2026-04-28 09:55:47.1777370147
$\lim_{x \to n\pi} \frac{M^{2}\cos(2Mx)}{\cos(2x)} = M^2$?
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For any integers $n$ and $M$ we have: $$\lim_{x\rightarrow n\pi}\frac{M^2\cos2Mx}{\cos2x}=\frac{M^2\cdot1}{1}=M^2.$$ It's not true if M is not an integer number.