Find the value of a that makes the following function continuous on $(-\infty, \infty)$. $f(x)= \frac{4x^3+13x^2+13x+30}{x+3}$ if $x\lt-3$, $5x^2+3x+a$ if $x \ge -3$}?
2026-03-18 21:34:43.1773869683
Limit and Function defined at a Point of Discontinutiy.
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when x goes to from left -3 limit of f(x) = 43
there fore for the continuity when x goes to -3 right limit of 5x^2+3x+a must be equal to 43
thus 5*9+3*(-3)+ a = 43
a=7