lim(d^2 --> infty) d - 1 = infty Is this valid notation, or must it be written using lim(d --> infty) instead? I would like to express that as d^2 tends to infinity, d - 1 tends to infinity as well. Is there a better way to write this?
2026-04-06 10:49:06.1775472546
Limit notation question
54 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
Consider that $d-1 $ is a function of $d^2$. Why sould it be $\sqrt{d^2}-1$ and not $-\sqrt{d^2}-1$?
For the first one, you get the limit $\infty$ and for the second one, $-\infty$.
You should probably change your notation.