If spectral radius of a square matrix $A$ is less than 1, then we know that $$\lim_{k \to \infty} A^k = 0.$$
Now, I want to know whether we can also conclude the following results? $$\lim_{k \to \infty} A^k (A^{T})^k = 0$$ where $A^{T}$ is the transpose of matrix $A$.
Hint: $A^T$ has the same eigenvalues as $A$. Then use algebraic limit rules.