Limit point of isolated singularities in complex analysis

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I came across the following conjecture (?) regarding (non-isolated) singularity in complex analysis: Suppose we have a function of a complex variable $f(z)$, which has poles at a set of points $\{z_n\},\ n=1,2,3, ...$ with a limit point $z_0 = \lim_{n\rightarrow \infty }z_n < \infty$. Then, $z_0$ must also be singular. My conjecture is that $z_0$ is a essential singularity.

One illustration of this is the function $f(z) = \frac 1 {e^{1/z}-1}$, which has simple poles at $z=\frac 1 {2\pi i n}$ ($n\in Z$) with residues $4\pi^2 n^2.$ This function has a essential singularity at $z=0$.

Do you think this is correct? If yes, is there any theorem regarding this?

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No, it is not correct. The concept of essential singularity is defined only for isolated singularities (as are the concepts of removable singularity and of pole). So, if a singularity is not isolated, it makes no sense to ask which type of singularity it is: removable, pole or essential.

In particular, it is not true that $0$ is an essential singularity of the function from your example.