I was solving for $x$ if
$$\lim_{n \rightarrow\infty}(\sin^{-1}(x))^n = 0$$
and got the answer as $x$ is all values except $0$ and $\{\pi/2+n\pi\}$ for all integers $n$. Am I right ?
I was solving for $x$ if
$$\lim_{n \rightarrow\infty}(\sin^{-1}(x))^n = 0$$
and got the answer as $x$ is all values except $0$ and $\{\pi/2+n\pi\}$ for all integers $n$. Am I right ?
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One has that $$\lim_{n\rightarrow\infty}|x|^n=\begin{cases}0, \quad \text{if } |x|<1 \\ 1, \quad \text{if }|x|=1 \\ +\infty, \quad \text{if } |x|>1\end{cases},$$ And in particular the first holds without absolute value.
Thus you need to find the inverse image of $(-1,1)$ under arcsin, i.e. $$\{x\in \mathbb{R}\mid |\arcsin(x)|<1\}\iff \{x\in \mathbb{R}\mid |x|<\sin(1)\}=(-\sin(1),\sin(1))$$