$f(x)=\frac{4z^3x^2-3x-7z}{3x^2+2x-1}$
Find all values of $z$ for which the limit of $x$ as $x$ goes to $-1$ of $f(x)$ exists?
$f(x)=\frac{4z^3x^2-3x-7z}{3x^2+2x-1}$
Find all values of $z$ for which the limit of $x$ as $x$ goes to $-1$ of $f(x)$ exists?
Copyright © 2021 JogjaFile Inc.
HINT
Since the denominator tends to zero, for the existence of the limit we need that
$$4z^3x^2-3x-7z \to 0 \iff 4z^3-7z+3=0$$