Suppose that $p(\lambda) = \lambda^3 -7\lambda + 6$ is a characteristic polynomial of the matrix $A$. Find the eigenvalues of $A$.
Is it possible to determine the order of the square matrix $A$?
Hint: if $r$ is a root of $p(\lambda)$, then $\lambda - r$ is a factor of $p(\lambda)$.
2026-04-09 11:05:23.1775732723
Linear algebra eigenvalues and eigenvectors
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Hint 1: if $p(\lambda)=\lambda^3-7\lambda+6$, then $p(1)=0$, so the polynomial is divisible by $\lambda-1$; can you find $q(\lambda)$ such that $$ p(\lambda)=(\lambda-1)q(\lambda) $$ and tell what's the degree of $q$? Can you find the roots of $q$?
Hint 2: the order of a matrix and the degree of its characteristic polynomial are…