A is an $2\times2$ matrix with $\operatorname{trace}=1$, and $\det A=-6$.
Prove that $(2A+5I)x=0$ has only trival solution.
I need to show that $(-A-\frac{5}{2}I)x=0$ Therefore I need to show that $-\frac{5}{2}$ is not eigenvalue but how could I conclude that?
Any help will be appreciated.
$$\lambda_1 + \lambda_2 = \textrm{tr}\ A\\ \lambda_1 \lambda_2 = \det A$$
Suppose $\lambda_1 = -\frac{5}{2}$. Then can $\lambda_2$ satisfy those relationships?