I'm doing a course on Applied Linear Algebra. Which, for the most part, is about applications in Octave, so there isn't much about the happenings behind a lot of the mechanics of everything.
I'm faced with the statement: "You can use the condition number to estimate the accuracy at which Octave solves for $x$ in $A x = b$. "First, we define the residual which is $A x - b$."
And I'm battling to understand this residual "$A x - b$". I'm trying to find some answers as to what this residual is and what to do with it.
Any help or reading material I can explore will be greatly appreciated.
By numerical solution of $Ax=b$ we obtain $\bar x$.
If $\bar x$ was an exact solution it should be $$A\bar x=b \implies A\bar x-b=0$$
since we always have some kind of numerical error or approximation we have a residual (vector) that is
$$r=A \bar x-b\neq 0$$
We can extimate the error by the norm |r|.