I have the function $f:\mathbb C^3 \to \mathbb C^3$, $f(x_1,x_2,x_3) = (4x_1 + 2x_2, x_1+4x_2+x_3, x_1+x_2+4x_3)^t$. $t$ stands for transposed
How can I determine if it is an linear application and it's matrix in a canonical basis?
I have the function $f:\mathbb C^3 \to \mathbb C^3$, $f(x_1,x_2,x_3) = (4x_1 + 2x_2, x_1+4x_2+x_3, x_1+x_2+4x_3)^t$. $t$ stands for transposed
How can I determine if it is an linear application and it's matrix in a canonical basis?
On
You can think that your function $f:{\Bbb C}^3\longrightarrow{\Bbb C}^3$ can be expressed as $$x=\left(\begin{array}{c} x_1\\ x_2\\ x_3\end{array}\right) \longmapsto f(x)= \left(\begin{array}{ccc} 4&1&1\\ 2&4&1\\ 0&1&4 \end{array}\right) \left(\begin{array}{c} x_1\\ x_2\\ x_3\end{array}\right),$$ so, by attending the above Hirshy and Keenan Kidwell's recommendation's you can settle your questions.
Just use the definition of linearity to check if this holds for the given function.
To find the corresponding matrix using the canonical basis take you should calculate $f(1,0,0), f(0,1,0)$ and $f(0,0,1)$ (that is the images of the canocical basis vectors) which gives you the columns of the matrix. The article on wikipedia might also be of interest to you.