I have been a bit rusty with my natural logs. I want to linearize this polynomial using logs. Does this look correct?
y = (v-x)/x^2
log(y) = log(v - x) - 2log(x)
log(y) = log(v) - log(x) - 2log(x)
log(y) = log(v) - 3log(x)
Thus, in y = mx + c ==>
y = log(y); m = -3 ; x = log(x); c = log(v)
This is incorrect.
$log(v-x) \not= log(v)-log(x)$
Further, the function you gave is not a polynomial, and thus cannot be linearized. Linearizing polynomials using logarithms shouldn't be possible as well.