Lipschitz constant for a second order nonlinear differential equation

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I'm trying to calculate the Lipschitz constant for a second order nonlinear differential equation:

$$y'' + y' + y^n = 0, \; y(0)=0, \; y'(0)= 0 \text{ and } n>1$$

Should I solve for $y(x)$ and differentiate the solution to find a bound ($L$, Lipschitz constant) on $\vert f'(x) \vert$? Or does it mean that I have to differentiate $f(x)= y'' + y' + y^n$? I would like some tips to proceed as this is my first calculation of this kind. Thanks in advance.

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To apply the formalism you use the Lipschitz constant for, you first need to transform the ODE into a first order system, \begin{align} y'&=v\\ v'&=-v-y^n. \end{align} Next we know that non-linear polynomials are never globally Lipschitz, you only get a local Lipschitz constant on a set like $|y|<R$. Then \begin{align} \|F(y_2,v_2)-F(y_1,v_1)\|_{\max}&=\max(|v_2-v_1|,|v_2-v_1+y_2^n-y_1^n|)\\ &\le |v_2-v_1|+nR^{n-1}|y_2-y_1|\\ &\le (1+nR^{n-1})\|(y_2,v_2)-(y_1,v_1)\|_{\max} \end{align} This is sufficient to prove uniqueness, but only local existence. No claim on the maximal domain follows from this bound.