Lipschitz Continuity of asymmetric function

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I have one basic following function.
$$ L(y,t)=\begin{cases} (1-\tau)(y-t)^2 &\text{ if } y<t, \\ \tau (y-t)^2 &\text{ if } y\geq t \end{cases} $$ where $y \in \mathbb{R}. \tau \in (0,1)$. Is that function is Lipschitz Continuous? If yes,then how it can be proved?

I have tried in the following way. By definition
\begin{align} &|L(y,t_1)-L(y,t_2)|\\ =&|(1-\tau)(y-t_1)^2+\tau(y-t_1)^2-(1-\tau)(y-t_2)^2-\tau(y-t_2)^2|\\ =&\left|(1-\tau)\left[(y-t_1)^2-(y-t_2)^2\right] +\tau\left[(y-t_1)^2-(y-t_2)^2\right]\right| \end{align}

I am stuck here..because it involves the terms of $y|y <t_1$ and $y|y\geq t_2$ and similarly for $< t_2$ and $\geq t_2$