$log_ab*log_ac$

Question

I was trying to make the thing tighter, but I don’t know how to expand $log_ab*log_ac$. What should I do? Specific problem: ${ln(3)}^2$

Answer 1

You cannot simplify further: using the change of base rule, you have:

$$\frac{\log b}{\log a} \cdot \frac{\log c}{\log a}$$ $$= \frac{\log b \log c}{\log^2 a}$$